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How to remove // inbetween the files contents?

 
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# 1  
Old 11-29-2012
How to remove // inbetween the files contents?
Hi Am Using unix Aix

Have a file name called FILE1
having the content of FILE1 is
Code:
cat FILE1
 
01/11/2012
03/11/2012
//
//
//
04/11/2012

I Need Output as:-
Code:
cat FILE1
01/11/2012
03/11/2012
04/11/2012

Wants to remove the backslash(//) can anyone help me pls ?
# 2  
Old 11-29-2012
Code:
awk '$0 != "//"' FILE1

# 3  
Old 11-29-2012
Code:
 
sed -e 's|//||g'   -e '/^$/d' FILE1

# 4  
Old 11-29-2012
Code:
grep [0-9] FILE1
grep -v // FILE1

# 5  
Old 11-30-2012
some lazy one :

Code:
awk '/.../' FILE1

Code:
grep ... FILE1

---------- Post updated at 12:48 AM ---------- Previous update was at 12:45 AM ----------

Code:
$ cat tst

01/11/2012
03/11/2012
//
//
//
04/11/2012
$ grep ... tst
01/11/2012
03/11/2012
04/11/2012
$ awk '/.../' tst
01/11/2012
03/11/2012
04/11/2012
$

This User Gave Thanks to ctsgnb For This Post:
Corona688
# 6  
Old 12-02-2012
Quote:
Originally Posted by Scott
Code:
grep [0-9] FILE1

That's a command which will be at the mercy of the contents of the current/working directory, for getting the intended results.

If the working directory has files/directories named with a single digit, then the shell will expand the glob [0-9] to the name/s of those files/directories and the grep will search with the wrong expression/string and/or in wrong files (if multiple filenames match the glob).
# 7  
Old 12-02-2012
Some more Smilie
Code:
grep -v ^/ file

Code:
grep '[^/]' file

Code:
awk -F/ \$1 file

Some awks:
Code:
awk NF-2 FS= file

Code:
sed \\-//-d file

 
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