How to archive old files from the recently added 10 files?


 
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Old 11-08-2012
Question How to archive old files from the recently added 10 files?

Hi there, I am very new to unix and having trouble with a fairly simple statement:

Code:
 
cd /user
ls -t -c1 | sed -ne '11,$p' | mv xargs archive/


What I want the code to do is sort all files in a directory by timestamp, select all of the files after the 10th file, and then move those files to an /archive folder.

When I execute this statement it throws a "file not found" error, is there any obvious reason why this isnt working?

Thanks
 
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AR(1)							      General Commands Manual							     AR(1)

NAME
ar, aal - archivers SYNOPSIS
ar [dmpqrtx][abciluv] [posname] archive [file ...] aal [dpqrtx][clv] archive [file ...] EXAMPLES
ar r libc.a sort.s # Replace sort.s in libc.a ar rb a.s libc.a b.s # Insert b.s before a.s in libc.a DESCRIPTION
Ar allows groups of files to be put together into a single archive. It is normally used for libraries of compiled procedures. Aal is like ar, but is to be used with the ACK compiler. The following keys are allowed: d: Delete. Ar will delete the named members. m: Move named files. Ar expects a, b, or i to be specified. p: Print the named files (list them on stdout) q: Quickly append to the end of the archive file. r: Replace (append when not in archive). t: Print the archive's table of contents. x: Extract The keys may optionally concatencated with one or more of the following: a: After posname b: Before posname c: Create (suppresses creation message) i: Before posname l: Local temporary file for work instead of /tmp/ar.$$$$$ u: Replace only if dated later than member in archive v: Verbose SEE ALSO
anm(1), asize(1), nm(1), size(1). AR(1)