UNIX for Dummies Questions & Answers

I've just begun using/studying Unix and I've run into a problem. I'm attempting to write a script that will replace a string within a textfile with another string, backing up the file before editing it.

This is what I have so far, but I'm getting a "command not found" error.

example input: myscript dog cat text.txt

Code:

#!/bin/csh
mv $3 $3.bak

sed "s/$1/$2/g" $3.bak > $3

If anyone can point me into the right direction, it would be greatly appreciated.

example input: myscript dog cat text.txt

I assume you want to command-line arguments.

Check this out.

Code:

#! /bin/csh

if ( "$#" != 3 )  then
echo " Only 3 arguments are required" 
else
mv "$3" "$3.bak"
sed -e "s/$1/$2/g" "$3.bak" > "$3"
endif

Vino

Hi Vino, thank you for your reply.

This was a really stupid problem. To fix the issue, all I had to do was add the full command directory. ie: /usr/bin/sed "s/$1/$2/g" $3.bak > $3 .

I wish I had come by this simple fix before spending hours on it.