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SED capturing information from a variable

 
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# 1  
Old 10-03-2012
SED capturing information from a variable
Hi

I can't get this line to work. I need to capture what is between Home and plugin_out, where the .* is located.
Code:
RUN=`echo '${TSP_FILEPATH_PLUGIN_DIR}' | sed -e 's^/results/analysis/output/Home/\(.*\)/plugin_out/g'`;
echo ${RUN};

I'm getting the error
sed: -e expression #1, char 51: unterminated `s' command
# 2  
Old 10-03-2012
Code:
sed -e 's#.*/Home/\(.*\)/plugin_out/.*#\1#g'

NOTE: .* is greedy. It will capture from first "/Home/" to last "/plugin_out/", so the g (global) is useless in this case.
Last edited by rdrtx1; 10-03-2012 at 01:36 PM..
This User Gave Thanks to rdrtx1 For This Post:
jdilts
 
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