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1. UNIX for Beginners Questions & Answers
Hi,
I am trying to use variable output in awk to append a string to a word in a line. But that is not happening. Could you please help me on this.
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2. Shell Programming and Scripting
Hi,
I have identified how to use command chaining as per below on a file, to capture the header of a file, as well as the line containing the C: drive.
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Filesystem Size Used Avail Use% Mounted on
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3. Shell Programming and Scripting
Hi Experts,
I am trying to get system output to capture inside awk , but not working:
Please advise if this is possible :
I am trying something like this but not working, the output is coming wrong:
echo "" | awk '{d=system ("date") ; print "Current date is:" , d }'
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4. Shell Programming and Scripting
hi i want to find the size of a folder and assign it to a variable and then compare if it is greater than 1 gb.
i am doin this script, but it is throwing error....
#!/bin/ksh
cd . | du -s | size = awk '{print $1}'
if size >= 112000
then
echo size high
fi
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5. Shell Programming and Scripting
Hi all,
Hope someone can help me out here.
I have this BASH script (see below)
My problem lies with the variable path.
The output of the command find will give me several fields. The 9th field is the path. I want to captured that and the I want to filter this to a specific level.
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6. Shell Programming and Scripting
Hi Experts,
I am trying to assing a value of current 'Mon DD' to the variable following way:
l_day=date '+%b %d'
Unfortunately, at the time of run, it says ' +%b %d: not found'
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7. Shell Programming and Scripting
I have a fixed width text file data.txt delimited by pipe. My requirement is to replace the second column values by *. Problem is that when tried access the shell variable in the awk program, value of shell variable is not printed instead only the name of the variable is printed. Please help to... (4 Replies)
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8. Shell Programming and Scripting
Hi,
I want to access a variable outside the awk program. My program is as below:- I can not access the exact value of k (See the last line of the program).
#!/usr/bin/sh
j=10
k=1
#k is declared outside awk
awk '
BEGIN {
i=1;
j1="'"$j"'"
printf("\n ## Value of j1 is %d ##", j1);
... (2 Replies)
Discussion started by: shouvik.mitra
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9. Shell Programming and Scripting
I am running a program which probably calla script within, this script executes in a pop window and control returns back to main program.
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10. Shell Programming and Scripting
Hi,
I made a small awk program just to test array variables.
I couldn't find anything wrong with it.
But it doesn't give out valid numbers.( just 0.00 )
Do you see any problem that I didn't see?
Thanks in advance!
Here is the program:
##################################
BEGIN {
FS =... (4 Replies)
Discussion started by: whatisthis
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