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# 8  
Old 08-03-2012
They are not commands. $ls does not run ls.

If you do ls=$(ls), then delete all your files, $ls will still show the files. You didn't store ls in a variable -- you stored the stuff ls printed into a string.

And the name $ls is not special. You could have done slartibartfast=$(ls) and it'd make absolutely no difference to what happens. The name of the variable is not important. All you're getting is the contents of something you stored.

They're not commands, they're variables. They don't do anything. They don't run anything when you use them. They don't change unless you change them yourself. They just hold strings.

You've got a very fundamental misunderstanding here, of the sort which could end up very badly for you if you mistake one for the other. You need to go back a bit and learn about commands and variables.
Last edited by Corona688; 08-03-2012 at 05:13 PM..
# 9  
Old 08-03-2012
Me and the others here try to explain to you, JD_Sal, that you need to learn to tell variables from commands and their outputs, even if they have identical names. This is very basic stuff you need for all your shell scripting and what have you.
# 10  
Old 08-04-2012
Variable and Command
Thanks
I understand, sorry for the sloppy wording on my part.
JD_Sal
 
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