echo date


 
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Old 06-14-2005
echo date

Hi,

How to display date using echo command.
I tried "echo date" , it prints "date" not actual date
only date command prints actual date.

Thanks
 
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DATETIME.SETTIMESTAMP(3)						 1						  DATETIME.SETTIMESTAMP(3)

DateTime::setTimestamp - Sets the date and time based on an Unix timestamp

       Object oriented style

SYNOPSIS
public DateTime DateTime::setTimestamp (int $unixtimestamp) DESCRIPTION
Procedural style DateTime date_timestamp_set (DateTime $object, int $unixtimestamp) Sets the date and time based on an Unix timestamp. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $unixtimestamp - Unix timestamp representing the date. RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. EXAMPLES
Example #1 DateTime.setTimestamp(3) example Object oriented style <?php $date = new DateTime(); echo $date->format('U = Y-m-d H:i:s') . " "; $date->setTimestamp(1171502725); echo $date->format('U = Y-m-d H:i:s') . " "; ?> Procedural style <?php $date = date_create(); echo date_format($date, 'U = Y-m-d H:i:s') . " "; date_timestamp_set($date, 1171502725); echo date_format($date, 'U = Y-m-d H:i:s') . " "; ?> The above examples will output something similar to: 1272508903 = 2010-04-28 22:41:43 1171502725 = 2007-02-14 20:25:25 NOTES
Using the Unix timestamp format to construct a new DateTime object is an alternative when using PHP 5.2, as shown in the example below. Example #2 DateTime.setTimestamp(3) alternative in PHP 5.2 <?php $ts = 1171502725; $date = new DateTime("@$ts"); echo $date->format('U = Y-m-d H:i:s') . " "; ?> The above example will output something similar to: 1171502725 = 2007-02-14 20:25:25 SEE ALSO
DateTime.getTimestamp(3). PHP Documentation Group DATETIME.SETTIMESTAMP(3)