I want to be able to spot double spaces in code and then also replace it with a single space. Double spaces sometimes occur accidentally in code, but most often they are indents or seperate code from comments ("//"). In summary: I want to replace double spaces with single spaces where they do not appear at the beginning of the line and do not appear prior to "//".
How do I do this in for instance sed?
Thank you for your prompt answer. First of all, I think it should be this:
ie replacement of a double space with a single space instead of removal of the double space ("s/ / /g").
Secondly, the following test case has issues:
is unaffected: lines with a double space and indented with spaces is unaffected.
How would I correct it?
Thank you for your answer. Your code also replaces double spaces prior to the comment delimiter ("//"). So that the following:
turns into the following
In brief there are the following cases:
and should turn into the following:
Grateful to anyone looking into this.
---------- Post updated at 17:34 ---------- Previous update was at 10:13 ----------
This problem is still vexing me. I believe there should be a simpler solution. In essence we are dealing with the following pattern:
a series of spaces
some code, with or without double / triple / etc spaces
(optionally) a series of spaces
(optionally) some comment with or without double / triple / etc spaces
The operation should be to leave 1, 3 and 4 alone and only replace the double spaces with single spaces from sub-pattern 2, the code. It should be possible to do this in a single sed statement.
Something like:
Can someone give some pointers on how to do this?
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TT0000013101640|
HCAMBLAMCNB010|Jul 3 2012 11:14AM|
HARYANA|
Bangali Mohalla |
TCL-UBR|9368040005|9355264655|9218509220|NULL
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