Working with file-names


 
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# 1  
Old 06-04-2012
Working with file-names

Hello forum,

I am new to shellscripting.

My first goal is to write a script that verifies that for each file in one path there is an associated one in another path.

The association is deviated by a distinct 'part' of the filename(s). Therefore I wanted to work with substitution.

Here is what I have so far:
Code:
for i in /my/source/path/*
 do
  var=basename $i
  echo ${var//cutme/""}
 done

I expected to put every filename reduced by the string 'cutme' to stdout. But it will tell me it has not sufficient privileges. I think it tries to rename the actual filename, but I just want to work with a 'copy'.

How can I work with filenames without actually changing it?

regards
# 2  
Old 06-04-2012
Try:
Code:
var=$(basename $i)

or
Code:
var=${i##*/}

# 3  
Old 06-04-2012
It worked.
Thank you Scrutinizer.

So
Code:
var=$(some)

means copy the value to a new variable?
# 4  
Old 06-04-2012
This is called command substitution.
 
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