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Question on Ramdom Number

 
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# 1  
Old 05-19-2005
Question on Ramdom Number
Hi all,

How do I get a ramdom number from 11 to 20 in every loop (loop runs 1000 times).

please let me know.

Thanks
# 2  
Old 05-19-2005
What shell are you using?
bash has builtin pseudo-random number support.

in bash this:

rnd=$((${RANDOM} %10 + 11))

would assign a random number between 11 and 20 to the variable rnd.

edit: depending on the version, this may also exist in ksh, if I remember correctly it exists in pdksh.
# 3  
Old 05-19-2005
Quote:
Originally Posted by jingi1234
Hi all,

How do I get a ramdom number from 11 to 20 in every loop (loop runs 1000 times).

please let me know.

Thanks
.... and 'loop' refers to what exact programming language/environment? [shell, perl, awk....]
# 4  
Old 05-19-2005
I am in Kshell. I need in kshell in less number of lines Smilie

Thanks
# 5  
Old 05-19-2005
need from 0 to 36. Thanks
# 6  
Old 05-19-2005
Quote:
Originally Posted by jingi1234
I am in Kshell. I need in kshell in less number of lines Smilie

Thanks
non-shell dependent way using awk - one line Smilie:

Code:
   rnd=`nawk 'BEGIN{srand(); printf int(rand() * 100 % 36) }'`

Last edited by vgersh99; 05-19-2005 at 05:24 PM..
# 7  
Old 05-19-2005
vgersh99 -

put your code inside a tight loop, echo $rnd and you'll see the problem with it.

Plus, not everyone has nawk... Smilie Me, for example.
 
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