UNIX for Dummies Questions & Answers

hi ,

I have a directory where the files were listed in format directory, date,etc.. and then : buildname->/apps/versions/buildname/build number

I use the below awk command which deletes all junk so it gives me /apps/versions/buildname/build number

Code:

ls -ltr |awk '{print $11}'|sort

I only want the buildname and build number only from /apps/versions/buildname/build number.

can someone tell how to add sed command to the above awk command to achieve it, or any other way to do it.

Please tell us what system, what shell and show some sample input and output lines.

Code:

ls -lrt | awk -F\/ '/\//{print $(NF-1) $NF }'

Thanks @itkamaraj,
Below command works.

Code:

ls -lrt | awk -F\/ '/\//{print $(NF-1) $NF }'

, just gave me the build name and build number.

The above solution is simple. Just to fool around:

Code:

ls -ltr |awk '{print $11}' | tr '/' '\n' | tail -2 | tr '\n' '/' | sed 's/\/$//g'

works too.

Code:

ls -lrt | awk -F\/ '/\//{print $(NF-1) $NF }'

This gave be the build name and build number but without space, how do i get to display build name with build # without space between build name and build number.

Try print $(NF-1),$NF