Date from file name


 
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# 1  
Old 04-15-2012
Date from file name

Hello,

I have a source file with the following naming convention,

Code:
WALGREENS_20120414003410.zip
WALGREENS_20120415003410.zip

Based on the file name I have to determine if it is a current day file and then process it

I will have to extract this *20120415* from the file name *20120415003410* to determine if it is current day file.

Can somoene please tell me how do I achieve this using korn shell.

Thanks
Pavan

Last edited by methyl; 04-17-2012 at 01:44 PM..
# 2  
Old 04-15-2012
One idea:

Code:
ls -1d WALGREENS_`date '+%Y%m%d'`*\.zip 2>/dev/null | while read today
do
         echo "This file contains todays datestamp: ${today}"
done


Last edited by methyl; 04-15-2012 at 03:36 PM.. Reason: missing quotes (in case dir contains spaces)
# 3  
Old 04-15-2012
Date from file name

Thank You
 
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