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define length of variable

 
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# 1  
Old 03-31-2005
define length of variable
I have a variable with a value of "05". When I add one to that variable, using the command: CURR_YY=`expr $CURR_YY + 1`, I get the value of "6", losing the leading zero (which is needed for passing to another script). How do I keep the leading zero?

Thank you!
# 2  
Old 03-31-2005
In KSH you can do this as follows:

typeset -R2 -Z CURR_YY=05
echo $CURR_YY

05

(( CURR_YY += 1 ))

echo $CURR_YY

06

Thomas
# 3  
Old 03-31-2005
Code:
#!/bin/ksh

typeset -Z2 a=6

echo "before->[${a}]"
((a=a+1))
echo "after->[${a}]"

# 4  
Old 03-31-2005
Although we have korn shell here, the first line in our scripts set the environment to bourne shell (.#!/bin/sh), so the typeset command does not work. I apologize for not putting that in the initial posting. I'm still learning Smilie
# 5  
Old 03-31-2005
Code:
#!/bin/sh

a='06'
echo "before->[${a}]"
a=`expr ${a} + 1|sed 's/^/0/'`
echo "after->[${a}]"

# 6  
Old 03-31-2005
What happens in the year 2010? Smilie
# 7  
Old 04-01-2005
I don't need to use the century in this code, so the code will work as I need it to.
 
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