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UNIX for Dummies Questions & Answers

Decoding a string

 
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# 8  
Old 03-19-2012
You can use regular expression match

Code:
if [ "${ch}" =~ "[0-9]" ]

# 9  
Old 03-19-2012
the match is not working as expected:
Code:
#!/bin/bash
len=`echo $1|wc -c`
a=$1
for((i=0;i<=$len-1;i++))
do
ch=${a:$i:1}
echo $ch
if [ "${ch}" =~ "[0-9]" ]
then
res=${ch}
else
res=`echo "$res",`
fi
done

Code:
pandeeswaran@ubuntu:~/training$ bash RunLength_decode 3a
3
RunLength_decode: line 14: [: =~: binary operator expected
a
RunLength_decode: line 14: [: =~: binary operator expected

RunLength_decode: line 14: [: =~: binary operator expected

# 10  
Old 03-19-2012
Try with double brackets.. like this:
Code:
if [[ "${ch}" =~ "[0-9]" ]]

# 11  
Old 03-19-2012
Which bash version you are using

there was a change between 3.1 and 3.2

if its 3.2 try

Code:
 
if [[ "${ch}" =~ [0-9] ]]

With out double quotes on regex.

Thanks Balasuri for correction Smilie
# 12  
Old 03-19-2012
@max_hammer: I don't think [ "$x" =~ [0-9] ] would work on bash 3.2 either.

I'm using GNU bash, version 3.2.25 and [ "$x" =~ [0-9] ] doesn't work. Regex matching is not supported by single square brackets.
This User Gave Thanks to balajesuri For This Post:
pandeesh
# 13  
Old 03-19-2012
Code:
if [[ "${ch}" =~ [0-9] ]];

does the trick
# 14  
Old 03-19-2012
Thanks balajesuri for correction and information.

I am using ksh and single bracket works fine for ksh. Smilie
 
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