UNIX for Dummies Questions & Answers

Hi,
I am trying to write a small script that validates if there exist files that start with a pattern in a given directory. Below is the piece of my script:

Code:

 
#!/usr/bin/ksh
BTFDIR=/opt/ships/temp
    if [ -e ${BTFDIR}/btf_daily_file_summary*.dat ]
    then
    echo 'found'
    else
    echo 'not found'
    fi

When I run this script, I am getting "test: argement expected" error when I execute it in current shell. However, when I execute in a new shell, it is giving me expected result as below.
Here are my questions in this regard: Why is this script behaving differently in these two scenarios? What should I change to fix this issue? Is there any better way to achieve this requirement?

Moderator's Comments:

Do not post technical questions in the "contact mods and admins" forum. Thread moved.

Code:

#! /usr/bin/ksh
BTFDIR=/opt/ships/temp
for x in `ls $BTFDIR`
do
    echo "$x" | grep -q "btf_daily_file_summary.*.dat"
    if [ $? -eq 0 ]
    then
        echo $x
    fi
done

It is because there is no "test -e" in ksh. You should be using "test -f".

I guess that your "sh" allows "test -e". The shebang line is ignored when you do "sh scriptname".

Quick fix is to change the shebang line in the script to match your "sh" or to change the test so it is valid in ksh.