UNIX for Dummies Questions & Answers

Hello,

I'm trying to run a one line for loop from the CRON. This is the exact command

Code:

 /bin/bash for file in $(/bin/find /opt/local/edw_extract/logs -name "*.log"); do /bin/cat /dev/null > $file; done

This will run from the command successfully.



When I schedule this to run it will error out and produce the following output

Code:

/bin/bash for file in $(/bin/find /opt/local/edw_extract/logs -name "*.log"); do /bin/cat /dev/null > $file; done

produced the following output:

sh: syntax error at line 1: `(' unexpected


Could someone explain the proper way to do this?
Is this even possible?


Thank You.


mhauff

Try this:

Code:

/bin/bash -c 'for file in $(/bin/find /opt/local/edw_extract/logs -name "*.log"); do > $file;  done'

See if that helps. Generally, complex commands in cron cause way more trouble than just writing a simple shell script that you invoke from cron. And you save nothing worth worrying about in performance

I'd check the environment variables. it seems they need to be specified for cron

Thanks to everyone for the quick responses. Jim's response worked. Thank you.