UNIX for Dummies Questions & Answers

I assign the variable

Code:

name=`find . -type f | awk -vR=$num '{if (NR == R) {print; exit}}`

which returns the name of a file in "$num" ordered in the folder to the variable $name.
I want to use IF and determine if the file is a NORMAL text file (does not contain an extension), the command will display the file content, ELSE, exit the script.
What command can I use?
Thanks in advance.

---------- Post updated at 07:40 PM ---------- Previous update was at 07:33 PM ----------

i can even use the command:

Code:

name=`ls -1p | grep -v "/$" | awk -vR=$num '{if (NR == R) {print; exit}}`

so that the $name only contains the name of the file ( in find command, $name contains the path to the file) but ls command does not display files in subdirectories.

Not sure what OS or shell you're using, but if you have the 'file' command available this may help point you in the right direction. If a file is some type of text file, the 'file' command should return it in it's description of the file:
i.e.
file testme
testme: Bourne-Again shell script text executable

Code:

[ $(file "$name" | grep -o -c 'text') == 1 ] && cat $name || echo "$name is not a text file"

Hope this helps.