UNIX for Dummies Questions & Answers

Hi!I'm new in this forum,also in shell scripting! :P
I'd like to help me with an issue!the project wants to make a variable with a directory(any) and then print all executable files of this directory,sorted by size!Thank you!

seems like a homework

post this in homework section

Nope!just practicing!i found random exercises and i'm trying to practice on shell scripting!(sorry for my terrible english! )

what you tried so far ?

my problem is passing a directory into a variable...i've thought this : dir_name=$(dirname $0)
now to print the executable files sorted by size i wrote this:
echo "executable files by size order:"
find $dir_name -type -f -perm -og+x | sort -nr

First let's get the "find" right: We're looking for any executable file so we need to check User, Group and Other permissions for the Executable bit. Within the protected brackets of this command the two standalone "-o" switches mean "OR".

Code:

find "${dir_name}" -type f \( -perm -u+x -o -perm -g+x -o -perm -o+x \)

Now ... the output from "find" will be a straight list of filenames which does not mention the size of the file.

ok!thanks for this by the way!now with this i can have a list with the executable file in directory dir_name...
i can sort them now with this command?
find "${dir_name}" -type f \( -perm -u+x -o -perm -g+x -o -perm -o+x \) | sort -nr