UNIX for Dummies Questions & Answers

Code:

#!/bin/bash

function check_num_args()

{
        if [ $# -eq 0 ]; then
                echo "Please provide a file name"
        else
                treat_as_file $*
        fi
}


function treat_as_file()
{
        numFiles=$#
        for((i=1;i<=$numFiles;i++));do
        echo $i
        done
}

check_num_args $*

Hi,

I'm new to this and am having trouble with my code above. In my function treat_as_file(), I want to display the parameters that have been passed into it. If for example when I run my file, I pass parameters 'file1' file2' 'file3', I want my code to echo 'file1' file2' 'file3'. At the moment it is displaying 1 2 3.

I have tried changing it to echo $$i but this displays my process id + i, and I have also tried echo \$$i but this displays $1 $2 $3.

Your help would be appreciated.
Thanks