UNIX for Dummies Questions & Answers

Hi,

I have to acheive the below logic in the script.

I have a file which has many columns and one of them is "File Names" and there will be only one such column name.

Eg., cat File1
Number of files:10
File Names: ABC, DEF, RTY,URE
....
...
...

The column will contain the different file names seperated by comma and each file names should be compared with the file names available in a unix directory for its presence. if the file is present with this name, script will be success or it should fail. eg., based on the above mentioned data, a file called ABC should be in a directory and similarly DEF, RTY and URE.
and there can be one file or can be more than one. eg., it can only be ABC or ABC and RTY or ABC, DEF, RTY,URE.

Can someone please help me with this?

Thanks
Vijay

Code:

#!/bin/sh

if ! [ -f "File1" ]
then
        echo "Data file doesn't exist" >&2
        exit 1
fi

IFS=" ," # Split awk's output on spaces and commas.
# in awk, match line beginning with 'File Names', print stuff after :, then quit
for FILE in $(awk -F: '/^File Names/ { print $2 ; exit }' File1)
do
        if ! [ -f "$FILE" ]
        then
                echo "$FILE missing" >&2
                exit 1
        fi
done

exit 0

thank you very much Corona688.

this works perfect.. can you please tell me how to write the error message to a file? i want to capture the $FILE missing message to a file...

---------- Post updated at 07:46 PM ---------- Previous update was at 07:21 PM ----------

I figured it out.. i have created a file and appended error message to that file.

thanks!

One more way ..

Code:

nawk -F: '/File Names:/{gsub(/,/," ",$2);print "ls -ltr "$2}' infile | sh
[ $? -eq 0 ] && echo "Success" || echo "Failure"