Can someone help me with the following 2 objectives?
1) The following command is just an example. It gets a list of all print jobs. From there I am trying to extract the printer name. It works with the following command:
Problem is, I want to be able to omit these multiple lines:
So it looks like this:
Now, each line is actually different (because each one is its own print job), but because I use awk to just get the name of the printer, the end result displays the printer name for however many print jobs there were. I just want one instance of each printer name.
2) In the previous section, I want to reduce the number of lines returned to one per printer. Before I do, I want to count how many there are. For example, how many time was My_office_printer listed.
OK, here's the deal (my head is starting to hurt here)
I need to get the number of Jobs that are printed on each printer, per date, by user.
What you did earlier helped get the printer name and number of jobs. I tried to change it a little, so I can get some more info (the date) out of it.
So, if I enter "testguy" as my user (variable from other script), then I want the following returned:
I will then need to be able to use each line as a variable so I can find a way to "graph" this later....
I'll try to explain it better, but I thought I would post this anyway...
In case it helps, here is all the info returned by
-W "completed" show all jobs that have been completed, not waiting to complete. The -o will show for all printers. There is a -u flag, but grepping the user seems to work better.
This is one job entry. The actual result is many lines, all with this format.
I need to strip the unique job number from the name of the printer (different for each entry, in this case it's -494). The 23552 is the number of bytes the job is, don't need that, and I don't need the time and year. So, really, what I need here is $1,$2,$4,$5,$6, and $1 has to be without the -494 or whatever the unique job number is).
Last edited by TheCrunge; 02-22-2005 at 04:21 PM..
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