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Help with grep & count in ksh

 
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# 15  
Old 10-06-2011
Thanks Scrutinizer.

But the grep does not give me the count of words present in the file.

Thanks

---------- Post updated at 03:22 PM ---------- Previous update was at 03:19 PM ----------

I used this to test what it does
Code:
var=`nawk '{n+=gsub("esdev","",tolower($0))}END{print n}' $path`
echo value is $var

the echoed value is 5 for the following file
Quote:
No.esDEV.Queue|No.Receive.Queue|||n|120|No_User||No_User|
No.Send.Queue|No.Receive.Queue|||n|120|No_User||No_User|
# 16  
Old 10-06-2011
That's right but I figured that since you were only testing for zero occurences, that did not matter. If you need the count then you could try something like this:
Code:
if occ=$(grep -ci esprd infile)
then 
  echo "failure with $occ occurrences"
  exit 1
else
  echo success
fi

# 17  
Old 10-06-2011
Quote:
Originally Posted by Green_Star
Thanks Scrutinizer.

But the grep does not give me the count of words present in the file.

Thanks

---------- Post updated at 03:22 PM ---------- Previous update was at 03:19 PM ----------

I used this to test what it does
Code:
var=`nawk '{n+=gsub("esdev","",tolower($0))}END{print n}' $path`
echo value is $var

the echoed value is 5 for the following file
for the quoted file, I get the expected value of 1 for '$var'
# 18  
Old 10-07-2011
Quote:
Originally Posted by vgersh99
for the quoted file, I get the expected value of 1 for '$var'
oh really. Nice.

Which shell are you using? I am using Korn Shell. Thanks
# 19  
Old 10-07-2011
Quote:
Originally Posted by Green_Star
oh really. Nice.

Which shell are you using? I am using Korn Shell. Thanks
either ksh or bash.
# 20  
Old 10-07-2011
That should work in just about any shell though. There's not a lot to it -- awk does everything.

It may be that your awk is misbehaving. What's your system?
# 21  
Old 10-07-2011
OOH!!! Now it works.

Thanks a lot to all of you. It was really nice help from everyone of you.
 
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