UNIX for Dummies Questions & Answers

Hi

i have shared object file called libvp.so , which is

Code:

ELF 32-bit LSB shared object, Intel 80386, version 1 (SYSV), dynamically linked, not stripped

i am calling this program on architecture 64-bit MSB machine ( zLinux)

is there anyway to convert between LSB to MSB ??

what is the impact ?

any help is much appreciated , thank you

MSB and LSB are the order which a processor handles bytes in. All x86 and x86_64 processors, from the first 8086 to whatever marketing term Intel now calls their modern processors, are LSB byte order. Most other processors, like POWER and SPARC and MIPS and Z-series, run in MSB byte order. MSB is supposedly the more 'technically correct' order.

There's no such thing as an MSB 80386 and, running zlinux, you're on some kind of Z-architecture processor or other, which has more in common with 70's mainframes than modern PC's. Your executable isn't the wrong byte-order, it's the wrong processor entirely.

I don't think you're going to be able to convert it. The instructions won't make any sense to your processor. If you can't find a binary for your architecture, you may have to compile one from scratch.

Even if the library and OS had the same endianness, you would also need a 64-bit version of the library unless you have a 32-bit ecosystem on the 64-bit platform.