UNIX for Dummies Questions & Answers

Hi i have a command in windows which captures the filenames with the same pattern and route it to another file.

for example filetest_20110921, filetest_20110922,filetest_20110923 etc

I would like to know the command in UNIX/LINUX for the same. The command which i am using in Windows is

cmd \c dir <dir>\filetest*.txt /b /a:-d > <dir>\All_File_Names.txt

Please let me know what can be the equivalent command in UNIX.

Thanks,
Mansur

Code:

ls filetest*.txt > All_File_Names.txt

Could you please let me know how to mention the directories?

Code:

ls filetest*.txt /any_dir/anyfile*.any_extension /some/other/random/txt/file*.txt > All_File_Names.txt

ls filetest*.txt /any_dir/anyfile*.any_extension /some/other/random/txt/file*.txt > All_File_Names.txt
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Is the following command is true?
ls filetest*.txt/incoming/filetest*.txt/ > All_File_Names.txt

Imagine you were typing "del *.txt *.pdf" into CMD, then stripped out the space, what would "del *.txt*.pdf" do in CMD? It'd complain "no such file or directory" because there's no file matching *.txt*.pdf. By stripping out the spaces you're mushing everything together into one big expression. The same happens when you do that in shell.

UNIX shell is very different from windows CMD in that it handles * for you. In CMD, if you do echo *.txt it prints *.txt. In shell, when you do echo *.txt it fills in *.txt with every matching filename!

'ls' isn't necessary for *, wildcards work with any command in shell. ls is just used here to make it print them one per line instead of all on one line.

I still did not understand whether the command which was given is correct or not?