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Help with awk (making simple/advanced ini parser)

 
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# 1  
Old 07-18-2011
Help with awk (making simple/advanced ini parser)
Hello

I'm searching some kind of example (or ready-made solution, but I don't really want it, because I want to learn awk more), to make something like a parser in awk for something like this (I put example, because I don't really know how to explain this):
Code:
[something]
line1=1
line2=0
line3=1
line4=1

[something]
line1=1
line2=0
line3=5
line4=1

[something]
line1=1
line2=0
line3=2
line4=1

[something]
line1=1
line2=0
line3=5
line4=15

And I want to have output like this:
Code:
[something]
line1=1
line2=0
line3=5
line4=1

[something]
line1=1
line2=0
line3=5
line4=15

I mean... I want to export from one file whole lines from "[something]" to "\n" which have line3=5
I have to notice, that lines aren't in same amount, for example there can be:
Code:
[something]
line1=1
line2=0
line3=5
line4=15

But can be also:
Code:
[something]
line1=1
line2=0
line3=5
line4=15
line5=1
line6=6

etc.

Is it possible to made? And sorry for my english, I'm still learning Smilie

Hope, that you will understand me.
jormung
# 2  
Old 07-18-2011
Well, if you want a hint to start with, then consider this: if you run AWK like this:
Code:
awk 'code' RS= file

then it will split file to records separated by empty lines, not by newline characters, so first record (NR==1) will be
Code:
[something]
line1=1
line2=0
line3=1
line4=1

second (NR==2) will be
Code:
[something]
line1=1
line2=0
line3=5
line4=1

and so on. You can then search each of those records for "line3=5" with regular expression.
This User Gave Thanks to bartus11 For This Post:
jormung
# 3  
Old 07-18-2011
Thanks, about this RS="" I even tried RS="\n[something]", which is wrong as I think, but I don't really have idea how to write this.
Now I made, that I'm getting this specify line or whole lines, but I have to make for it loop for as I think, right?
And how exactly could I search in whole lines? Because for now, I'm making it in this way (specify line and I'm looking for a way to search all lines):
Code:
awk '{if(NR == 2 && $4 == "line3=5"){print $0} }' RS= file.txt

It is some kind of succes for me Smilie

And about loop, I tried to make it in this way, but it won't send me anything:
Code:
awk '{ble=0; for(NR == 1;  ble<=NR; NR++){if ($4 == "line3=5") {print $4;} } }' RS= file.txt

In my thinking, teoretically it should increase NR by 1, but it seems, that I don't really know how to build a loop "for"
# 4  
Old 07-18-2011
To search whole record you can use // predicate, like this:
Code:
awk '/line3=5/' RS= file.txt

Check if it is giving proper result.
This User Gave Thanks to bartus11 For This Post:
jormung
# 5  
Old 07-18-2011
Yes, it's working exactly how I wanted, even I didn't dream, that it could be that short code.
Thank You so much.

Or maybe not, damn, with longer things (not like with my example) it just copy whole ini instead of specify lines, hmm strange... So maybe I'll try to make something with this loop
Last edited by jormung; 07-18-2011 at 08:36 AM..
# 6  
Old 07-18-2011
Through Sed..
Code:
sed -n 'H;/^$/{x;/line3=5/s//&/p};${x;/line3=5/s//&/p}' inputfile

# 7  
Old 07-18-2011
Quote:
Originally Posted by jormung
Yes, it's working exactly how I wanted, even I didn't dream, that it could be that short code.
Thank You so much.

Or maybe not, damn, with longer things (not like with my example) it just copy whole ini instead of specify lines, hmm strange... So maybe I'll try to make something with this loop
Do those longer things have each block separated by an empty line?
 
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