UNIX for Dummies Questions & Answers

Hi, I would just like to know how to get the file with the max filename on a directory and get rid of all the others. For example, in directory A:/ i have the ff files:

APPLE2001
APPLE2002
APPLE2003
GRAPE2004

what I want to get is the max in files whose filenames start with APPLE*, hence, my expected result is APPLE2003. Then, when I get this file, how would I rename it to say, FINALAPPLE? And remove all files starting with APPLE*?

Thanks!

Code:

 
FileName=`ls -lrt APPLE* | awk '{print $9}' | sort -nr | head -1`
echo $FileName
#test the above output and if you satisified then uncomment the below one
#mv $FileName FINALAPPLE && rm -rf APPLE* || echo "Move is not success"

Thanks, itkamaraj. This is working perfectly.

---------- Post updated at 11:59 PM ---------- Previous update was at 11:22 PM ----------

oh, one more thing, what's the use of awk '{print $9}'?

just execute ls -lrt APPLE*

and execute ls -lrt APPLE* | awk '{print $9}'

you will get to know the difference

actually, we are extracting only the filenames (9th column) from the ls -lrt output

ok..I get it now.. Thanks again!