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passing coloumn value to system function in awk

 
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# 1  
Old 07-07-2011
Question passing coloumn value to system function in awk
Hi all,

I have a file which contain data like
Code:
1|2009-12-12
2|2010-02-28
3|2009-02-29

i have to validate that second coloumn have proper date

i tried like

Code:
awk -F "|" ' !system("touch -d $2 file1 2> /dev/null" ) '

but its not printing any thing

but when i try using hard coded value it works
Code:
 awk 'BEGIN{if(!system("touch -d 2009-12-23 file1 2> /dev/null")) print "okay"; else print "not valid"}'
okay
 
 awk 'BEGIN{if(!system("touch -d 2009-02-29 file1 2> /dev/null")) print "okay"; else print "not valid"}'
 
not valid

what i am doing wrong ? SmilieSmilie

Thanks in advance
# 2  
Old 07-07-2011
Try:
Code:
awk -F "|" ' !system("touch -d "$2" file1 2> /dev/null" ) '

# 3  
Old 07-07-2011
Thanks it worked Smilie

i missed the quoted Smilie

i was wonderdering i am passing parameter wrong way
 
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