Dividing a column by it's first number


 
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# 22  
Old 06-27-2011
Code:
#!/usr/bin/perl
open I,"$ARGV[0]";
chomp(@x=<I>);
for ($i=0;$i<=$#x;$i++){
  @y=split / +/,$x[$i];
  for ($j=0;$j<=$#y;$j++){
    push @{$c[$j]},$y[$j];
  }
}
for ($i=0;$i<=$#y;$i++){
  for $j (@{$c[$i]}){
    $d[$i]=$j if ($j!=0 && !$d[$i]);
  }
  @one=grep {$_ == 1} @{$c[$i]};
  if ($#one==$#{$c[$i]}){
    @{$c_out[$i]}=map {("0")} @{$c[$i]};
  } else {
    for ($j=0;$j<=$#{$c[$i]};$j++){
      $c_out[$i][$j]=$c[0][$j]*$c[$i][$j];
    }
  }
}
for ($i=0;$i<=$#x;$i++){
  for ($j=0;$j<=$#y;$j++){
    if ($j<2){
      print $c[$j][$i],"  ";
    } else {
      print $c_out[$j][$i],"  ";
    }
  }
  print "\n";
}

This User Gave Thanks to bartus11 For This Post:
# 23  
Old 07-11-2011
How can I modify this to have the script divide the columns by the 119 line instead of the first line? Smilie

---------- Post updated at 07:39 PM ---------- Previous update was at 12:07 PM ----------

I tried replacing:

Code:
  @one=grep {$_ == 1} @{$c[$i]};

with
Code:
  @one=grep {$_ == 119} @{$c[$i]};

but it didn't work...
# 24  
Old 07-12-2011
The above script is not dividing by first column, but multiplying. To multiply by 119th column use:
Code:
#!/usr/bin/perl
open I,"$ARGV[0]";
chomp(@x=<I>);
for ($i=0;$i<=$#x;$i++){
  @y=split / +/,$x[$i];
  for ($j=0;$j<=$#y;$j++){
    push @{$c[$j]},$y[$j];
  }
}
for ($i=0;$i<=$#y;$i++){
  for $j (@{$c[$i]}){
    $d[$i]=$j if ($j!=0 && !$d[$i]);
  }
  @one=grep {$_ == 1} @{$c[$i]};
  if ($#one==$#{$c[$i]}){
    @{$c_out[$i]}=map {("0")} @{$c[$i]};
  } else {
    for ($j=0;$j<=$#{$c[$i]};$j++){
      $c_out[$i][$j]=$c[118][$j]*$c[$i][$j];
    }
  }
}
for ($i=0;$i<=$#x;$i++){
  for ($j=0;$j<=$#y;$j++){
    if ($j<2){
      print $c[$j][$i],"  ";
    } else {
      print $c_out[$j][$i],"  ";
    }
  }
  print "\n";
}

# 25  
Old 07-13-2011
What I am trying to do is to divide by the each column by its 119 line... not multiply by the 119 column.
# 26  
Old 07-13-2011
Then try this:
Code:
#!/usr/bin/perl
open I,"$ARGV[0]";
chomp(@x=<I>);
for ($i=0;$i<=$#x;$i++){
  @y=split / +/,$x[$i];
  for ($j=0;$j<=$#y;$j++){
    push @{$c[$j]},$y[$j];
  }
}
for ($i=0;$i<=$#y;$i++){
  for $j (@{$c[$i]}){
    $d[$i]=$j if ($j!=0 && !$d[$i]);
  }
  @one=grep {$_ == 1} @{$c[$i]};
  if ($#one==$#{$c[$i]}){
    @{$c_out[$i]}=map {("0")} @{$c[$i]};
  } else {
    for ($j=0;$j<=$#{$c[$i]};$j++){
      $c_out[$i][$j]=$c[$i][$j]/$c[$i][118];
    }
  }
}
for ($i=0;$i<=$#x;$i++){
  for ($j=0;$j<=$#y;$j++){
    if ($j<2){
      print $c[$j][$i],"  ";
    } else {
      print $c_out[$j][$i],"  ";
    }
  }
  print "\n";
}

This User Gave Thanks to bartus11 For This Post:
# 27  
Old 10-19-2011
Hi All!

I have a question related to my old question (but much simpler!)

if I have a file like this:
Code:
8  10  12  14  16  18  0  2  6
2   4    6    8    10  12  16  18  10
 6  8  12  16  18  0  2  2  6 
 2  2  2  2  2  2  2  2  2  
10  12  16  4  8  16  4  16  0
 8  10  14  16  0  4  8  12  14

And I want to divide all the lines by line 4 for example (except column 1) to get:

Code:
8  5  6  7  8  9  0  1  3
1  2  3  4  5  6  8  9  5
6  4  6  8  9  0  1  1  3 
2  1  1  1  1  1  1  1  1
10  6  8  2  4  8  2  8  0
4  5  7  8  0  2  4  6  7

What is the simplest script that I can use?
Thanks!

---------- Post updated 10-19-11 at 11:05 AM ---------- Previous update was 10-18-11 at 01:57 PM ----------

Does my question make sense? Is it clear?
 
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