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How to print number before argument?

 
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# 1  
Old 05-02-2011
How to print number before argument?
Hey everyone,

I need to write a script that will display the number of the argument before displaying the argument itself. Here's what I have so far:

for arg in "$@"
do
echo $#:$arg
done

This returns the sum of all arguments preceding the arguments themselves.

$(script) a b c
3:a
3:b
3:c

But I want...

$(script) a b c
1:a
2:b
3:c

Thanks
# 2  
Old 05-02-2011
One way:
Code:
$ cat nargs
#! /bin/ksh

i=0
while ((i<$#)) ; do
        ((i=i+1))
        eval arg=\$$i
        echo ${i}:${arg}
done
exit 0
$ ./nargs a b c d
1:a
2:b
3:c
4:d
$

This User Gave Thanks to Perderabo For This Post:
unclepickle1
 
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