UNIX for Dummies Questions & Answers

Hi all,

I am still learning my way around unix commands and I have the following question.
I have a website and I want to search for all the html pages that don't contain a certain js file. The file I am searching for is located under /topfolder/js/rules.js . So I assume in my grep search I could search for either "rules.js" or better if possible "/topfolder/js/rules.js".

I want to search topfolder and all files inside that directory and print the results to a file.
Any help I can get is much appreciated.
Thank you

You should try grep -v


-v, --invert-match
Invert the sense of matching, to select non-matching lines. (-v is specified by POSIX.)

This my command to match the string:
find ./ -name '*.html' -exec grep -l "/top/js/file1.js" {} \; 2>/dev/null 1>./output.txt &

The command above prints all the html files that have a reference to the js file.

Unfortunately, I am unable to use -v or -L. -vl prints all the files with or without the js reference. -L only doesn't print anything.

Could you please tell me what I am doing wrong? Tx

Code:

find ./ -name '*.html' |
while read filename
  grep -q '/top/js/file1.js' $filename || echo $filename > output.txt
done

Try that. Be sure your grep supports -q first.

So I put the above in a script and when I executed it I got an error.

$ ksh rule1
rule1: ^M: not found
rule1[2]: syntax error at line 4 : `done' unexpected

Please know that I am still learning about Unix/Linux.
Also how do I check if my ksh supports grep -q ?

gnu grep & gnu find:
find ./ -name '*.html' -exec grep -L "/top/js/file1.js" {} \; 2>/dev/null 1>./output.txt

-L is without match, -l is with match. also, the -v is not useful here, as grep with the -L effectively searches the whole file, and the -v is for the usual single line search (programmatically, I'm sure it's differently, but effectively is what counts here)