UNIX for Dummies Questions & Answers

This will fetch all file(s) created on today.

Code:

ls -lrt | awk '{print $6$7" "$9 }' | grep `date +%b""%d` | awk '{print $2}'

---------- Post updated at 03:47 AM ---------- Previous update was at 03:41 AM ----------

make sure that month is Initcap

Code:

mon='Apr'
dd='25'
ls -lrt | awk '{print $6$7" "$9 }' | grep $mon $dd | awk '{print $2}'

Using find will output filenames only for all files modified not only within the last 24 hours, but all files modified today and from the beginning (midnight) of yesterday.

No need to 'touch' a file at a certain timestamp.

Code:

find . -maxdepth 1 -mindepth 1 -type f -mtime -1 -daystart | sort

NOTE: tested on GNU find.

Hi PalaniSVR, The code you provided is cool and serves my reqmt..But how do i get the result into a variable? please help

The problem with "find -mtime -1", even with -daystart, is that unless it starts on the first second each day, there can be gaps or duplications in the find. For precision, it is better to touch a marker file and find -newer $marker_file, using two markers as I described to bracket either N exact calendar days or one exact batch since last run.

Even then, a file being modified ongoing could be included in multiple days, in different versions, of course.

I happened to schedule the script and somewhat it back fired. Instead of picking those files which created on a particular day, it picked almost all the files..Please let me know how to handle this..

---------- Post updated at 07:21 AM ---------- Previous update was at 12:40 AM ----------

Code:

ls -lrt | awk '{print $6$7" "$9 }' | grep `date +%b""%d` | awk '{print $2}'

fetches only files for a particular day, but i need to get whatever files it pulls into a variable and copy those files to a different location(path)...Please help

I usually grep for 'MMM DD ..:' if I go that way, to avoid picking up prior years. The touch/-newer method does not suffer from ls formatting challenges.

Maybe you need to use nawk not awk?

Pickett, whatever are your ideas, can you pen them down...AM being a Novice here. Please let me know how do i take the result into a variable and copy the same over to an other location...below is what am expecting(i might be wrong but something in those lines)

Code:

new='ls -lrt | awk '{print $6$7" "$9 }' | grep `date +%b""%d` | awk '{print $2}''
echo $new
cp $new somelocation/path