UNIX for Dummies Questions & Answers

It's easy as pie to get the date minus one day on opensolaris:

Code:

date -d "-1 day" +"%Y%m%d"

run this command on our crappy Solaris 10 machines however (which I'm guessing doesn't have GNU date running on it) and you get:

Code:

date: illegal option -- d
date: illegal option -- 1
date: illegal option --
date: illegal option -- d
date: invalid argument -- y
usage:  date [-u] mmddHHMM[[cc]yy][.SS]
        date [-u] [+format]
        date -a [-]sss[.fff]

This is so so annoying. I can't put GNU date on these unix machines, so how can I get the date -1 day?

Cheers

---------- Post updated at 01:37 PM ---------- Previous update was at 01:21 PM ----------

nevermind... this does it...

Code:

DATE_STAMP=`TZ=UTC+24 date +%y%m%d`; echo $DATE_STAMP

Tricky, using the time stamp in hours! However, the problem is you used the Solaris date, not the GNU/LINUX date. You can get trusted Solaris binaries or source and configure/make your own GNU utilities. Solaris may even have them on their CDs now, since I saw them a lot. You may have them in /usr/local/bin or some such place not high enough on your $PATH.

ksh93 and bash have date operations built-in.

See my datecalc script.

Or my tm2tm C program, anything +- anything to anything, give or take some integer overflow. https://www.unix.com/shell-programmin...bsd-linux.html

Humm, I do not think that bash has date operations builtin other than printf %T integer formatting option.

Sorry, it was inconceivable to me that ksh93 did things that bash could not!