UNIX for Dummies Questions & Answers

Hey guys/gals,

Am having trouble getting an 'if statement' to play nice..


I am playing with a script and need 'if' to check whether "y" or "Y" has been
entered and if not to exit.
In previous scripts I was playing with there would normally be a Y and a N response
possibility so each response would have their own 'then statement'.

In this case I want to ensure that if neither y or Y is entered that the scriupt exits.

I was hoping to get away with ;

Code:

echo -ne "the question requiring the y/n response ; "
read input
if [ "$input" != "y" ] || [ "$input" != "Y" ] ; then 
echo "blah blah" 
exit
fi

But no dice

I have tried using '-ne' but also no luck, using '!==' results in a binary operator expected error..
Just can' t seem to get it to do what I would like.

Any ideas on how best to get 'if' to confirm that the input is NOT the desired input ?

Many thanks !

The problem is in [ "$input" != "y" ] || [ "$input" != "Y" ], it will always true.

if you input y, the second condition is trun, if you input Y, the first condition is trun, if you input N or n or other words, both conditions are true.

Code:

echo -ne "the question requiring the y/n response ; "
read input
if [ "$input" == "y" ] || [ "$input" == "Y" ] ; then
  echo "Good"
else
  echo "blah blah"
exit
fi

Ah, that does makes perfect sense.. my mind is obviously not functioning right just yet

Will play some more, thanks for your prompt response rdcwayx !