UNIX for Dummies Questions & Answers

hey

Thanks for your post,

I took upon your example code and tried it, but i am getting 'unrecognized history modifier'. I am running the command on the previously attached file 'walle.txt'

---------- Post updated at 02:47 PM ---------- Previous update was at 02:16 PM ----------

Hey guys,

So along with the following code:

walle.txt | sed "s/'/ /g" | xargs -n1 | sort | uniq -c - this runs a word count of all of the words in the text file 'walle.txt' but some of the output contains punctuation and multiple words e.g A.?/, or A/B.
how would i combine this with sed "s/[\"',.;?!:]/ /g;s/ */ /g" walle.txt
which removes punctuation but still outputs the word frequency?
Is this possible?
Can somebody help me please?

Kind regards

Why don't you just paste the text into: Word Frequency Counter
Anyway, here is the results:

Hmmm.... very interesting unorthodox approach

Code:

strings walle.txt | head -5521 | tail +91 | sed "s/[][^\"'(\`),=\.;?!:#%+-]/ /g;s/  */ /g" | tr ' [:upper:]' '\n[:lower:]' | grep -v '^[0-9]*$' | sort | uniq -c >wordcount.txt

---------- Post updated at 11:23 AM ---------- Previous update was at 09:23 AM ----------

Check the file at the different step and see if it can fit your needs

Code:

strings walle.txt | head -5521 | tail +91 >f1
sed "s/[][^\"'(\`),=\.;?!:#%+-]/ /g;s/  */ /g" f1 >f2
tr ' [:upper:]' '\n[:lower:]' <f2 >f3
grep -v '^[0-9]' f3 | sort >f4
uniq -c f4 >f5
sort -k 1n f5 >f6

Code:

strings walle.txt | head -5521 | tail +91 >f1
sed "s/[][^\"'(\`),=\.;?!:#%+-]/ /g;s/  */ /g" f1 >f2
tr ' [:upper:]' '\n[:lower:]' <f2 >f1
grep -v '^[0-9]' f1 | sort >f2
uniq -c f2 >f1
sort -k 1n f1 >f2