UNIX for Dummies Questions & Answers

Hi,

I have a file that contains multiple lines e.g.

Code:

/Plane/Wing/Engine/Rotorblades

I cannot use

Code:

 print $4

as the directories will be different lengths.

All i would like to do is print the very last column in each line in the file i.e. in this case, Rotorblades.

The code i was trying to use was;

Code:

cat VehicleTest | awk '{split($1,a,"/");print $(NF)}'

I have also tried

Code:

awk '{FS = "//"  ;printf etc}'

but that doesnt work either.

Where am i going wrong in my syntax?

Any help would be greatly appreciated.

Thanks in advance

Code:

awk -F/ '{print $NF}'

Code:

while read a ; do echo ${a##*/} ; done <VehicleTest

Code:

<VehicleTest xargs -i basename {}

Code:

sed 's:.*/::' VehicleTest

Code:

nawk -F/ '{$0=$NF}1' VehicleTest

Thanks pludi that worked a dream

Did you give a try to the sed solution ?

As far as i've tested, the awk solution of my previous post work with nawk or "linux" awk (i guess the "standard" awk does not support the $0= assignment).