UNIX for Dummies Questions & Answers

I am trying to analyse a large file of sequencing data, example of first 10 lines below,

@HWUSI-EAS656_0044_FC:7:1:2447:1039#GCAATT/1
GNCTATGGCTTGCCGGGCTCAGGGAAGACAATCATAGCCATGAAAATCATGGAAAAGATCAGAAAAACATTTCAA
+HWUSI-EAS656_0044_FC:7:1:2447:1039#GCAATT/1
VBVZVSVZZ[aaW^^aaZ\WdacdaWXYK\SEFZFLTMHSZ^]^YYFHRSacWWcBBBBBBBBBBBBBBBBBBBB
@HWUSI-EAS656_0044_FC:7:1:2632:1042#ATAGTA/1
TNGTACATCTAAAAGCTCTAGAAAAAAAGGAAGCAAATTCACCCAAGAGGAGTAGATGGCAGGAAATAATCAAAC
+HWUSI-EAS656_0044_FC:7:1:2632:1042#ATAGTA/1
NBVWP]Y_]`dbacfggggegegggg``ecaacffcfffcdffff^ffccdfacf^^cac\dadaffcccff\da
@HWUSI-EAS656_0044_FC:7:1:2977:1039#ACCACT/1
ANGTAGCCATCTTTTTACTTTTTAATATGTGGCAGGATATCATTAAGTTGCCTGGGCTAAGGGCTGAGAGGATGA

In order to run the data through the barcoding file I need to remove the letters between characters including # until the /1
I have tried using

sed 's/#*\/1$/\/1/g' <./s_7_sequence.txt >./s_7.txt

to save the data as a new file called s_7.txt without the #***** but whenever I run this it runs but the new file looks exactly the same as the old. I have tried running sed to remove anything to check I'm not being completely useless and have had success with

sed 's/#G//g' <input >output

and this works fine but
obviously only removes the # and the first letter from the lines with #G.

I would appreciate any help at all to correct my sed command, I have now tried as many variations as I can understand but am a complete newby at this.

Thanks

Use:

Code:

sed -e 's:#.*/1$::' inputfile > outputfile

The regex #*/1$ was matching zero or more # followed by /1 at the end of the line. The addition of the . to match any character change the regex to match # followed by zero or more of any characters followed by /1 at the end of the line.