UNIX for Dummies Questions & Answers

Hi,

I want to determine whether my java application is pointing to the OS version of Java or the User installed Java version on my Unix box.

I am aware of the "java -version" command, however I am unsure if the version returned is the OS one or the user one.

Please help.
Ali.

It will be either the first one found in your $PATH or the one the user ( you?) has set in his environment...

I found two versions, both as desired using the "-fullversion"

confusion here still is which one is my java application pointing to -- the USR or the OS.

/usr/j2se/bin/java
/opt/java/jdk/jdk160/bin/java

Thanks.

And when you type :

Code:

which java

What do you get?

"which java" gives me "/opt/java/jdk/jdk160/bin/java"

does this mean that the application points to this location or just that it searches for the path and directory containing java...

echo $PATH gives /opt/java/jdk/jdk160/bin

are there any other environment variables i need to check or which java solves my doubt?

Thanks vbe in advance and for your patience

It means that you or with the account you just used will effectively execute the java found in /opt/java/jdk/jdk160/bin/
As I said some users may have defined another path...
It is usually the case when depending of software needs dont match with current default version, or developers testing last release...
on many boxes I administrate there are up to 6 versions... So by default javapath is NOT set, and so you customize according to your needs