awk variable substitution


 
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# 1  
Old 09-10-2004
awk variable substitution

for the command below, it looks for the 3rd field value matching "P" and printing it.

awk '{if ($3 == "P") print}' file

how would i express this if i use a loop to find more that 1 variable fro a list? this doesn't seem to work...

cat list | while read n
do
awk '{if ($3 == "$n") print}' file
done
exit


thanks, any input is appreciated.
adimuhan
# 2  
Old 09-10-2004
You need to pass in the variable to Awk. Use the -v switch

Code:
cat list | while read n
do
awk -v n="$n" '{if ($3 == n) print}' file
done
exit

 
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