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print average of duplicates

 
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# 8  
Old 11-09-2010
Quote:
Originally Posted by vgersh99
try this - with no fractions:
Code:
FNR==1 {header=$0;next}
{
  cntA[$1]++
  f2[$1]+=$2
  f3[$1]+=$3
}
END {
  print header
  for(i in cntA)
    printf("%s%s%.0f%s%.0f\n", i, OFS,f2[i]/cntA[i], OFS, f3[i]/cntA[i])
}

This code works well.
Thank you
# 9  
Old 11-09-2010
No, I meant, why are there no fractions, as on #1?

Maybe they are rounded, unless you do printf with a number of fractional digits allowed.
Last edited by DGPickett; 11-10-2010 at 03:14 PM..
 
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