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Appending sed output to variable

 
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# 1  
Old 10-24-2010
Appending sed output to variable
I want to append matched output and cat the results into an variable. but I've been running into problems. sed is printing result on to screen instead of appending the output to $CAPTURE. I'm stumped...how should i fix this?

Code:
contents of $TEST

10.0.0.1
10.0.0.2
10.0.0.3
10.0.0.4

Code:
expected data in $CAPTURE:

10.0.0.1
10.0.0.2
10.0.0.3

Code:
#!/usr/xpg4/bin/sh
export PATH="/usr/xpg4/bin:$PATH"

echo "$TEST" | sed -n 's/^10.0.0.1$/&/p' > $CAPTURE
echo "$TEST" | sed -n 's/^10.0.0.2$/&/p' > $CAPTURE
echo "$TEST" | sed -n 's/^10.0.0.3$/&/p' > $CAPTURE

# 2  
Old 10-24-2010
Code:
CAPTURE=$(echo "$TEST" | sed -n 's/^10.0.0.1$/&/p'
echo "$TEST" | sed -n 's/^10.0.0.2$/&/p'
echo "$TEST" | sed -n 's/^10.0.0.3$/&/p')

# 3  
Old 10-24-2010
Quote:
Originally Posted by jlliagre
Code:
CAPTURE=$(echo "$TEST" | sed -n 's/^10.0.0.1$/&/p'
echo "$TEST" | sed -n 's/^10.0.0.2$/&/p'
echo "$TEST" | sed -n 's/^10.0.0.3$/&/p')

thanks, but now I've another problem when:

contents in
$TEST
10.0.0.1
10.0.0.2
10.0.0.21
10.0.0.3
10.0.0.4

contents in
$CAPTURE
10.0.0.1
10.0.0.2
10.0.0.21
10.0.0.21 <-- duplicated entry? what happened?
10.0.0.3

Code:
#!/usr/xpg4/bin/sh
export PATH="/usr/xpg4/bin:$PATH"

TEST=$(echo 10.0.0.1
        echo 10.0.0.2
        echo 10.0.0.21
        echo 10.0.0.3
        echo 10.0.0.4
        )

CAPTURE=$(echo "$TEST" | sed -n 's/^10.0.0.1/&/p'
echo "$TEST" | sed -n 's/^10.0.0.2/&/p'
echo "$TEST" | sed -n 's/^10.0.0.21/&/p'
echo "$TEST" | sed -n 's/^10.0.0.3/&/p')

printf "$CAPTURE"

Last edited by jazzaddict; 10-24-2010 at 01:52 AM..
# 4  
Old 10-24-2010
you can maybe try delete others Smilie
Code:
# TEST=$(echo 10.0.0.1
        echo 10.0.0.2
        echo 10.0.0.21
        echo 10.0.0.3
        echo 10.0.0.4
        )

Code:
# echo "$TEST"| sed '/10.0.0.[123]$/!d'
10.0.0.1
10.0.0.2
10.0.0.3

Code:
# echo "$TEST"| sed '/10.0.0.[4]$/d'
10.0.0.1
10.0.0.2
10.0.0.21
10.0.0.3

if you want to your method
then try correct in below in your script (add $ char so means end of line )

Code:
TEST=$(echo 10.0.0.1
        echo 10.0.0.2
        echo 10.0.0.21
        echo 10.0.0.3
        echo 10.0.0.4
        )

CAPTURE=$(echo "$TEST" | sed -n 's/^10.0.0.1/&/p'
echo "$TEST" | sed -n 's/^10.0.0.2$/&/p'
echo "$TEST" | sed -n 's/^10.0.0.21/&/p'
echo "$TEST" | sed -n 's/^10.0.0.3/&/p')

printf "$CAPTURE"

# 5  
Old 10-24-2010
Code:
#!/usr/xpg4/bin/sh
export PATH="/usr/xpg4/bin:$PATH"

TEST="10.0.0.1
10.0.0.2
10.0.0.21
10.0.0.3
10.0.0.4"

CAPTURE=$(echo "$TEST" | eval sed -n \
$(for ip in 10.0.0.1 10.0.0.2 10.0.0.21 10.0.0.3
do
  printf "-e 's/^%s$/&/p' " $ip
done))

echo "$CAPTURE"

or even
Code:
#!/usr/xpg4/bin/sh
export PATH="/usr/xpg4/bin:$PATH"

TEST="10.0.0.1
10.0.0.2
10.0.0.21
10.0.0.3
10.0.0.4"

CAPTURE=$(for ip in 10.0.0.1 10.0.0.2 10.0.0.21 10.0.0.3
do
  echo "$TEST" | grep -w $ip
done)

echo "$CAPTURE"

# 6  
Old 10-24-2010
Alternatively, without the linefeeds in the variables and no external commands:

shell code:
  1. #!/usr/xpg4/bin/sh
  2. export PATH="/usr/xpg4/bin:$PATH"
  3. TEST="10.0.0.1 10.0.0.2 10.0.0.21 10.0.0.3 10.0.0.4"
  4. IPS="10.0.0.1 10.0.0.2 10.0.0.21 10.0.0.3"
  5. for i in $TEST
  6. do
  7.   for j in $IPS
  8.   do
  9.     if [ "$i" = "$j" ]; then
  10.       CAPTURE="$CAPTURE $i"
  11.     fi
  12.   done
  13. done
  14. printf "%s\n" ${CAPTURE# }
 
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