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Help Needed with Grep

 
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Top Forums UNIX for Dummies Questions & Answers Help Needed with Grep
# 8  
Old 10-06-2010
Hi Guy's

Thanks very much for your help, I've decided to settle on this command which works well.
Code:
grep "`date '+%b %e'`" /var/adm/messages > syslog.`date +%d%m%y`.log

Regards, Wynford Smilie
Last edited by Scott; 10-06-2010 at 08:15 AM.. Reason: Please use code tags
# 9  
Old 10-06-2010
I think we should use the "date" command to generate this date because the "awk" process won't work for a two-digit day-of-month. Also, what if there are no messages today?


However, following on from the original script.
Now we know what the log looks like, we could use "cut".

Code:
todays_date="`tail -1 /var/adm/messages|cut -c1-6`"
grep "${todays_date}" /var/adm/messages > syslog.`date +%d%m%y`.log



---------- Post updated at 12:13 ---------- Previous update was at 12:11 ----------

OOps. Posts crossed in the post. Please take wthomas last post as the finale.
 
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