UNIX for Dummies Questions & Answers

Hi,
Can anyone tell me if ii am right about this code.

Code:

 childid=0;
for (i=1;i<3;i++){
  if(childid=fork())
     break;
}
fprintf("Print process id's and so on");

First process comes to fork.Comes to break; breakes out of loop,prints and dies. Child Just created continues from the statement break;breakes oit of loop and prints. Therefore this output should give me print for 2 processes but instead keeps giving me output for 3 processes.

Can anyone try to clear this please..why it is printing 3 proceses

doesnt parent after fork goes to break; statement....This is output i am getting...

Code:

processID:10925  parent ID:10924  child ID:0
processID:10924  parent ID:10852  child ID:0
processID:10926  parent ID:10924  child ID:0

Why do you think the parent process won't execute the printf() statement?

It will but only once. After it forks it goes
to break. Then it comes out of loop and prints
and dies

this was my first try with forking....

Code:

childid=0; 
for (i=1;i<3;i++)  
     if(childid=fork())      
            break;

fprintf("Print processid%d  parentid%d  childid%d" , getpid,getparent,child);

But when i split fprintf() one line each....such as......

Code:

.....
.....
fprintf("Print processid%d" , getpid());
fprintf("Print parentid%d",getparent());
fprintf("print child%d\n",child);

My output gets messed up and parentid of one process get mixed up on same line with childid of different process and sometimes doesn't even print processid.Does this have anything to do with fprintf() function which holds data for output in the buffer.My assumption is that sometimes while one process is lets say on first line of its printf() cpu takes away its time and then gives it to second process. Second process maybe gets to second line of printf() and now tis time is taken away. Now in the buffer we have 3 things that need to be printed out. Am i correct on what is happening here??