UNIX for Dummies Questions & Answers

Hi All,

I am having a script which calculate checks the input feed and perform some function. When i am executing this script i am redirecting this to a output file. I want to know the redirected output file name inside my scripts. Is there is any way to get that .

like the same way we used to get the argument as $1 and so on


Thanks,
Arun

Probably no good portable way across *ix. But if you have lsof you can use the pid of the current running process (stored as $$) and do something like:

Code:

lsof -p $$ -a -d 1

That says find open files for the current process and (-a) only those associated with file descriptor 1.

Just one soln (maybe)...

that really does not make sense. handle I/O inside the script if you need to(see exec). Don't mess with output files handled outside your script or strange things can occur.

Or perhaps:

Code:

lsof -p 12220 -a -d 1 -F n

To get something easily parsed (grab the line beginning with "n")

Code:

lsof -p 12220 -a -d 1 -F n | sed -n 's/^n//p'

I don't suggest using lsof. It might not even be available on the system. If you need the file name pass it as an arugment but I would not write/read to that file inside the script.