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Cut a field from a line having quotes as delimiter

 
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# 1  
Old 08-18-2010
Cut a field from a line having quotes as delimiter
Hi ,

I have extract a single field from the 2nd row of a file of which the format is as given below

"Field1","Field2","Field3",...,"Field17",...
I need to cut Field17 as such (no quotes required)..

I give the command
head -2 file_name | tail -1 | cut -d "," -f17
But the output is coming as
"Field17" (with quotes) .. I need the Field17 without quotes

The command is not recognizing the quotes as a delimiter. Could you please suggest me a way?

regards,
Nivin
# 2  
Old 08-18-2010
Use double quotes as field separator:
Code:
head -2 file_name | tail -1 | cut -d "\"" -f34

Or with one awk command:
Code:
awk -F\" 'NR==2{print $34}' file_name

# 3  
Old 08-18-2010
Quote:
Originally Posted by Franklin52
Use double quotes as field separator:
Code:
head -2 file_name | tail -1 | cut -d "\"" -f34

Or with one awk command:
Code:
awk -F\" 'NR==2{print $34}' file_name

both of the commands worked and thanks a lot... Smilie
 
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