awk help


 
Thread Tools Search this Thread
Top Forums UNIX for Dummies Questions & Answers awk help
# 1  
Old 06-14-2004
awk help

I have 2 questions.
1. Using awk how do I specify two different actions based on the value of the first field on every record in a file.
2. How do I ask awk to output the current date as the last field on some records.

Here is the situation. if the value of the first field is 1, I need to print the entire record and today's date otherwise print just the record.

I am trying this on HP UX 11

Thanks in advance for any help.
# 2  
Old 06-14-2004
There are two ways. You can specify two pattern/action pairs...
Code:
awk -v date=$(date +%d-%b-%Y) '
    $1 == 1 { 
            print $0, date 
    }
    $1 != 1 {
            print $0 
    }
' file1 > file2

Or use an if..else statement...
Code:
awk -v date=$(date +%d-%b-%Y) '
    {
        if ($1 == 1) { 
            print $0, date 
        }
        else { 
            print $0 
        }
    }
' file1 > file2

# 3  
Old 06-14-2004
Thank you so much for the reply.

Yogr, I tried the code from the command prompt and it worked, but I think you could have your scripts in a file and specify -f option in the awk command to run against it. I tried to put the code within the quote in a file and I tried but didn't work. Any thoughts?
# 4  
Old 06-15-2004
Gee thanks for the -f tip. I wonder why it didn't work when you changed it. Perhaps it was something you did?
# 5  
Old 06-15-2004
Take a look at this. This is my awk command file, florida.awk

$1 == 1 {
print $0, date
}
$1 != 1 {
print $0
}

and this is how I run the command

$ awk -v date=$(date +%m/%d/%y) -f florida.awk florida.txt >output

I am getting the output but without the date.

Do you see any problem? Thanks.
# 6  
Old 06-15-2004
Yogr, forget about my previous post. I found out the problem. I didn't mention the field delimiter, I should have given the command like this,

$ awk -F"," -v date=$(date +%m/%d/%y) -f florida.awk florida.txt >output

That brings another question. Using -F flag I assume we are refering the field delimiter for the input file. It is not putting the delimiter in the output file. Where or how do you specify delimiter for the output file?

Thanks again for the help.
# 7  
Old 06-15-2004
You can set the field separators in the BEGIN action, e.g...

BEGIN {
FS=OFS=","
}
 
Login or Register to Ask a Question

Previous Thread | Next Thread

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

awk output yields error: awk:can't open job_name (Autosys)

Good evening, Im newbie at unix specially with awk From an scheduler program called Autosys i want to extract some data reading an inputfile that comprises jobs names, then formating the output to columns for example 1. This is the inputfile: $ more MapaRep.txt ds_extra_nikira_usuarios... (18 Replies)
Discussion started by: alexcol
18 Replies

2. Shell Programming and Scripting

Pass awk field to a command line executed within awk

Hi, I am trying to pass awk field to a command line executed within awk (need to convert a timestamp into formatted date). All my attempts failed this far. Here's an example. It works fine with timestamp hard-codded into the command echo "1381653229 something" |awk 'BEGIN{cmd="date -d... (4 Replies)
Discussion started by: tuxer
4 Replies

3. Shell Programming and Scripting

Passing awk variable argument to a script which is being called inside awk

consider the script below sh /opt/hqe/hqapi1-client-5.0.0/bin/hqapi.sh alert list --host=localhost --port=7443 --user=hqadmin --password=hqadmin --secure=true >/tmp/alerts.xml awk -F'' '{for(i=1;i<=NF;i++){ if($i=="Alert id") { if(id!="") if(dt!=""){ cmd="sh someScript.sh... (2 Replies)
Discussion started by: vivek d r
2 Replies

4. Shell Programming and Scripting

HELP with AWK one-liner. Need to employ an If condition inside AWK to check for array variable ?

Hello experts, I'm stuck with this script for three days now. Here's what i need. I need to split a large delimited (,) file into 2 files based on the value present in the last field. Samp: Something.csv bca,adc,asdf,123,12C bca,adc,asdf,123,13C def,adc,asdf,123,12A I need this split... (6 Replies)
Discussion started by: shell_boy23
6 Replies

5. Shell Programming and Scripting

awk command to compare a file with set of files in a directory using 'awk'

Hi, I have a situation to compare one file, say file1.txt with a set of files in directory.The directory contains more than 100 files. To be more precise, the requirement is to compare the first field of file1.txt with the first field in all the files in the directory.The files in the... (10 Replies)
Discussion started by: anandek
10 Replies

6. Shell Programming and Scripting

Comparison and editing of files using awk.(And also a possible bug in awk for loop?)

I have two files which I would like to compare and then manipulate in a way. File1: pictures.txt 1.1 1.3 dance.txt 1.2 1.4 treehouse.txt 1.3 1.5 File2: pictures.txt 1.5 ref2313 1.4 ref2345 1.3 ref5432 1.2 ref4244 dance.txt 1.6 ref2342 1.5 ref2352 1.4 ref0695 1.3 ref5738 1.2... (1 Reply)
Discussion started by: linuxkid
1 Replies

7. Shell Programming and Scripting

Problem with awk awk: program limit exceeded: sprintf buffer size=1020

Hi I have many problems with a script. I have a script that formats a text file but always prints the same error when i try to execute it The code is that: { if (NF==17){ print $0 }else{ fields=NF; all=$0; while... (2 Replies)
Discussion started by: fate
2 Replies

8. Shell Programming and Scripting

awk: assign variable with -v didn't work in awk filter

I want to filter 2nd column = 2 using awk $ cat t 1 2 2 4 $ VAR=2 #variable worked in print $ cat t | awk -v ID=$VAR ' { print ID}' 2 2 # but variable didn't work in awk filter $ cat t | awk -v ID=$VAR '$2~/ID/ { print $0}' (2 Replies)
Discussion started by: honglus
2 Replies

9. Shell Programming and Scripting

scripting/awk help : awk sum output is not comming in regular format. Pls advise.

Hi Experts, I am adding a column of numbers with awk , however not getting correct output: # awk '{sum+=$1} END {print sum}' datafile 2.15291e+06 How can I getthe output like : 2152910 Thank you.. # awk '{sum+=$1} END {print sum}' datafile 2.15079e+06 (3 Replies)
Discussion started by: rveri
3 Replies

10. Shell Programming and Scripting

Awk problem: How to express the single quote(') by using awk print function

Actually I got a list of file end with *.txt I want to use the same command apply to all the *.txt Thus I try to find out the fastest way to write those same command in a script and then want to let them run automatics. For example: I got the file below: file1.txt file2.txt file3.txt... (4 Replies)
Discussion started by: patrick87
4 Replies
Login or Register to Ask a Question