UNIX for Dummies Questions & Answers

array[0]=u
array[1]=n
array[2]=i
array[3]=x

#!/bin/sh

declare -a arr
len=`expr \`echo $var | wc -c\` - 1`
for i in $(seq 1 $len)
do
   arr[`expr $i - 1`]=$(echo $var | awk -vj=$i '{ printf substr($0, j, 1)}')
done

echo ${arr[0]}
echo ${arr[1]}
echo ${arr[2]}
echo ${arr[3]}

str=unix
eval array=($(echo $str | awk '$1=$1' FS=))

eval array=($(sed 's/./ &/g'<<<$str))

$ echo ${array[1]}
n

# a=unix;ix=0; for i in `fold -w1 <(echo $a)`; do array[ix]=$i; echo "$ix. variable of array->" ${array[ix]}; let ix=$ix+1; done
0. variable of array-> u
1. variable of array-> n
2. variable of array-> i
3. variable of array-> x

for i in $(seq 1 `echo ${#var}`)
do
     arr[`expr $i - 1`]=$(echo "$var" | awk -v i=$i '{print substr($0, i, 1)}')
done