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date format conversion

 
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# 1  
Old 05-22-2010
date format conversion
hi,

i have a file in which i get date format as 22/APR/2010...
now i want the date format to be in 22-04-2010

if the month changes to may the file should also have 05 as month....

pls help
# 2  
Old 05-22-2010
One way:
Code:
echo '22/APR/2010' |
awk -F"/" '{
  printf("%02d-%02d-%04d\n", $1, (index("JANFEBMARAPRMAYJUNJULAUGSEPOCTNOVDEC",$2)+2)/3, $3)
}'
22-04-2010

# 3  
Old 05-24-2010
thks franklin...can u pls explain the code... did not understand

regards
siva
# 4  
Old 05-25-2010
Quote:
Originally Posted by siva_nagarajan
thks franklin...can u pls explain the code... did not understand

regards
siva
Code:
(index("JANFEBMARAPRMAYJUNJULAUGSEPOCTNOVDEC",$2)+2)/3

The index function gives the position of the month of the string.
To get the month number the position number is increased with 2 and divide by 3.
Code:
Month:	Position:	Month number:

 JAN	  1		(1+2)/3 = 1
 FEB	  4		(4+2)/3 = 2
 MAR	  7		(7+2)/2 = 3

and so on...
 
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