The meaning of %s in printf


 
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Top Forums UNIX for Dummies Questions & Answers The meaning of %s in printf
# 22  
Old 05-07-2010
Yep, correct!
# 23  
Old 05-10-2010
Quote:
Originally Posted by cosmologist
I have this command like that has %s in it, I know %s calls a column, but I am not sure I understand which column (I mean for my case I can check the input file, but I want to know how is this %s used, how comes tha same symbo; gives different columns in one command line:

Code:
{printf "grep %s junk.all.dat | awk '$4<=%s{print $1, $2, $3, $4, $5}' | wc -l >> fitnumb.dat\n"}

Each %s give a different column in the output:

Code:
grep 3a junk.all.dat | awk '$4<=157.951{print $1, $2, $3, $4, $5}' | wc -l >> fitnumb.dat
grep 7a junk.all.dat | awk '$4<=118.793{print $1, $2, $3, $4, $5}' | wc -l >> fitnumb.dat
grep 9a junk.all.dat | awk '$4<=133.435{print $1, $2, $3, $4, $5}' | wc -l >> fitnumb.dat

Any idea how this %s works?
OKay, so I grunched this thread other than the first few posts.
In there no one mentioned how this line here:

Code:
{printf "grep %s junk.all.dat | awk '$4<=%s{print $1, $2, $3, $4, $5}' | wc -l >> fitnumb.dat\n"}

Is missing some arguments. At any rate... The %s are formatting strings that printf interprets to mean "print the associated argument as a string".

In this command, however, there are no arguments to printf.
On my system, this doesn't even work.

But making some modifications and attempting to stick with the original intent, I got this to work:

Code:
2158 -> cat a.awk
{
printf( "grep %s junk.all.dat | awk '$4 <= %s{print $1, $2, $3, $4, $5}' | wc -l >> fitnumb.dat\n",
  $1, $2 );
}

2159 -> date | awk -f a.awk
grep Mon junk.all.dat | awk '$4 <= May{print $1, $2, $3, $4, $5}' | wc -l >> fitnumb.dat

I'm probably late to the game -- but HTH.
 
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