10 More Discussions You Might Find Interesting
1. Homework & Coursework Questions
I am running a script in ksh to get the 2 months back date from system date.The below code is giving correct date output from putty command prompt.But while running the script is .ksh file it is giving the error below.Please suggest.
; d=a; y=a
m-=num
while(m < 1) {m+=12; y--}... (1 Reply)
Discussion started by: hini
1 Replies
2. AIX
As said in object, how can i obtain that?
In linux i use date -d "1 month" +"%m%Y".
Thanks i advance. (8 Replies)
Discussion started by: fabfisc
8 Replies
3. Shell Programming and Scripting
I have requirment to get last date of previous month and the first date of previous 4th month:
Example:
Current date: 20130320 (yyyymmdd)
Last date of previous month: 20130228 (yyyymmdd)
First date of previous 4th month: 20121101 (yyyymmdd)
In my shell --date, -d, -v switches are not... (3 Replies)
Discussion started by: machomaddy
3 Replies
4. UNIX for Dummies Questions & Answers
Hi All,
I am using the below code to get the year and month from date:
Below gives output like 201212.
dt=`date '+%Y%m'`
how do i get the previous month value(ie: subtract 1 from date)
example output:
dt=201211
Please help. :confused: (3 Replies)
Discussion started by: abhi_123
3 Replies
5. Shell Programming and Scripting
Hi,
i unable to get the last month date in AIX.
current date - one month
Based on the forums tried but did not find the relevent information.
Any help grealy appriciated.
Thanks
Suri. (3 Replies)
Discussion started by: onesuri
3 Replies
6. UNIX for Dummies Questions & Answers
Hi,
On any given day, I want to capture the month that has gone by - said otherwise, how do I capture last month?
expr date '+%m' - 1
Above expression is giving error.
Please advise
thanks
---------- Post updated at 09:28 AM ---------- Previous update was at 09:11 AM... (1 Reply)
Discussion started by: ab_2010
1 Replies
7. Shell Programming and Scripting
Hi All,
I need to find the previous month last day minus one day, using shell script. Can you guys help me to do this.
My Requirment is as below:
Input for me will be 2000909(YYYYMM)
I need the previous months last day minus 1 day timestamp. That is i need 2000908 months last day minus ... (3 Replies)
Discussion started by: girish.raos
3 Replies
8. UNIX for Dummies Questions & Answers
Hello,
I'm new to shell scripting.
We've develop a script which will grep a file on the search criteria, MON (Jan/Feb/Mar/etc). But we should set this sript in cron which will run on every first day of the month. The problem I'm having is, when I run the script, it is displaying the contents of... (7 Replies)
Discussion started by: suneelj
7 Replies
9. Shell Programming and Scripting
Hello,
I wanted to display the month for previous day date. Like, today date is 18-Nov-2008. So the previous date is 17-Nov-2008. The output should be November.
If the today date is 1-DEC-2008, then output should be NOVEMBER.
If the today date is 1-JAN-2008, then output should be DECEMBER.... (4 Replies)
Discussion started by: govindts
4 Replies
10. Shell Programming and Scripting
Hi, I'm new with Unix, I'm trying to get a last day of previous month with this format: %b %d %Y (example: Feb 25 2008).
Here is what I have so far.
#!/bin/ksh
cur_month=`date +%m`
cur_year=`date +%Y`
prev_month=$(($cur_month-1))
# Check to see if this is January
if
then
... (11 Replies)
Discussion started by: sirrtuan
11 Replies
CAL(1) BSD General Commands Manual CAL(1)
NAME
cal -- displays a calendar
SYNOPSIS
cal [-smjy13] [[month] year]
DESCRIPTION
Cal displays a simple calendar. If arguments are not specified, the current month is displayed. The options are as follows:
-1 Display single month output. (This is the default.)
-3 Display prev/current/next month output.
-s Display Sunday as the first day of the week. (This is the default.)
-m Display Monday as the first day of the week.
-j Display Julian dates (days one-based, numbered from January 1).
-y Display a calendar for the current year.
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: ``cal 89'' will not display a calen-
dar for 1989. Two parameters denote the month (1 - 12) and year. If no parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's.) Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
OTHER VERSIONS
Several much more elaborate versions of this program exist, with support for colors, holidays, birthdays, reminders and appointments, etc.
For example, try the cal from http://home.sprynet.com/~cbagwell/projects.html or GNU gcal.
BSD
June 6, 1993 BSD