UNIX for Dummies Questions & Answers

Alright, here's the deal. I'm running the following ruby script (output follows):

Code:

>> /Users/name/bin/acweather.rb -z 54321 -o /Users/name/bin -c
Clouds AND Sun 57/33 - Mostly sunny and cool

I want to just grab the "57/33" portion, but that's it. I don't want any other portion of the line. I want to be able to grab dynamically as everything changes depending on the weather.

My idea was to do something along the lines of

Code:

>> /Users/name/bin/acweather.rb -z 54321 -o /Users/name/bin -c | grep [0-9][0-9][/][0-9][0-9]

but this obviously returns the whole line.

Ideally I'd like to display the following (though I'm not sure it can be done without a script):
Any help would be great. Thanks!

---------- Post updated at 03:04 PM ---------- Previous update was at 02:45 PM ----------

I ended up just editing the script itself (doh!). I still would be interested to know if there's a way to grab just portions of text though...

Thanks!

Hey,

Please try this..

Code:

/Users/name/bin/acweather.rb -z 54321 -o /Users/name/bin -c |awk '{print $4}'|awk -F"/" '{print "High="$1 ; print "Low="$2}'

Thanks
Kantha

Code:

/Users/name/bin/acweather.rb -z 54321 -o /Users/name/bin -c | cut -d" " -f4 | awk -F"/" '{printf("high:%sF\nlow:%sF\n",$1,$2)}'

Code:

sed 's|.* \([0-9]*\)/\([0-9]*\) .*|High=\1\nLow=\2|'

just a small adition. the output format is missing the letter F

Code:

sed 's|.* \([0-9]*\)/\([0-9]*\) .*|High=\1F\nLow=\2F|'

Scrutinizer,

Can you explain the code please

thanks
kamaraj

High kamaraj,

It means save the two patterns of [0-9]* (with a / in between and spaces before and after) so that they can be referenced as \1 and \2 respectively. The patterns are in between \( and \) . Discard the rest. Note that a "|" is used as a separator for subsitition instead of "/ ".

S.